发信人: bmouse (乐不思鼠), 信区: Football
标 题: Re: 这个QB的rating是怎么出来的？
发信站: The unknown SPACE (Sun Oct 8 02:17:12 2000) WWWPOST
【 在 bmouse (乐不思鼠) 的大作中提到: 】
: 又看见一条，The maximum a passer can receive in any category is 2.375.
: 2.35/6*100=158.33333
:
NFL quarterback rating formula
The NFL rates its passers for statistical purposes against a
fixed performance standard based on statistical achievements
of all qualified pro passers since 1960. The current system
replaced one that rated passers in relation to their
position in a total group based on various criteria.
The current system, which was adopted in 1973, removes
inequities that existed in the former method and, at the
same time, provides a means of comparing passing
performances from one season to the next.
It is important to remember that the system is used to rate
passers, not quarterbacks. Statistics do not reflect
leadership, playcalling, and other intangible factors that
go into making a successful professional quarterback.
Four categories are used as a basis for compiling a rating:
• Percentage of completions per attempt
• Average yards gained per attempt
• Percentage of touchdown passes per attempt
• Percentage of interceptions per attempt
The average standard, is 1.000. The bottom is .000. To earn
a 2.000 rating, a passer must perform at exceptional levels,
i.e., 70 percent in completions, 10 percent in touchdowns,
1.5 percent in interceptions, and 11 yards average gain per
pass attempt. The maximum a passer can receive in any
category is 2.375.
For example, to gain a 2.375 in completion percentage, a
passer would have to complete 77.5 percent of his passes.
The NFL record is 70.55 by Ken Anderson (Cincinnati, 1982).
To earn a 2.375 in percentage of touchdowns, a passer would
have to achieve a percentage of 11.9. The record is 13.9 by
Sid Luckman (Chicago, 1943).
To gain 2.375 in percentage of interceptions, a passer would
have to go the entire season without an interception. The
2.375 figure in average yards is 12.50, compared with the
NFL record of 11.17 by Tommy O'Connell (Cleveland, 1957).
In order to make the rating more understandable, the point
rating is then converted into a scale of 100. In rare cases,
where statistical performance has been superior, it is
possible for a passer to surpass a 100 rating.
For example, take Steve Young's recordsetting season in
1994 when he completed 324 of 461 passes for 3,969 yards, 35
touchdowns, and 10 interceptions.
The four calculations would be:
• Percentage of Completions — 324 of 461 is 70.28
percent. Subtract 30 from the completion percentage (40.28)
and multiply the result by 0.05. The result is a point
rating of 2.014.
Note: If the result is less than zero (Comp. Pct. less than
30.0), award zero points. If the results are greater than
2.375 (Comp. Pct. greater than 77.5), award 2.375.
• Average Yards Gained Per Attempt — 3,969 yards
divided by 461 attempts is 8.61. Subtract three yards from
yardsperattempt (5.61) and multiply the result by 0.25.
The result is 1.403.
Note: If the result is less than zero (yards per attempt
less than 3.0), award zero points. If the result is greater
than 2.375 (yards per attempt greater than 12.5), award
2.375 points.
• Percentage of Touchdown Passes — 35 touchdowns in
461 attempts is 7.59 percent. Multiply the touchdown
percentage by 0.2. The result is 1.518.
Note: If the result is greater than 2.375 (touchdown
percentage greater than 11.875), award 2.375.
• Percentage of Interceptions — 10 interceptions in
461 attempts is 2.17 percent. Multiply the interception
percentage by 0.25 (0.542) and subtract the number from
2.375. The result is 1.833.
Note: If the result is less than zero (interception
percentage greater than 9.5), award zero points.
The sum of the four steps is (2.014 + 1.403 + 1.518 + 1.833)
6.768. The sum is then divided by six (1.128) and multiplied
by 100. In this case, the result is 112.8. This same formula
can be used to determine a passer rating for any player who
attempts at least one pass.

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